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Warn me when I try to sync upstream tests without requesting a commit.
This default invariably wastes my time, and I'm about the only person using the sync argument.
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1 changed files with 10 additions and 0 deletions
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@ -348,6 +348,11 @@ class MachCommands(CommandBase):
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self.ensure_bootstrapped()
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self.ensure_bootstrapped()
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run_file = path.abspath(path.join("tests", "wpt", "update.py"))
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run_file = path.abspath(path.join("tests", "wpt", "update.py"))
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kwargs["no_patch"] = not patch
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kwargs["no_patch"] = not patch
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if kwargs["no_patch"] and kwargs["sync"]:
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print("Are you sure you don't want a patch?")
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return 1
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run_globals = {"__file__": run_file}
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run_globals = {"__file__": run_file}
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execfile(run_file, run_globals)
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execfile(run_file, run_globals)
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return run_globals["update_tests"](**kwargs)
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return run_globals["update_tests"](**kwargs)
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@ -403,6 +408,11 @@ class MachCommands(CommandBase):
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self.ensure_bootstrapped()
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self.ensure_bootstrapped()
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run_file = path.abspath(path.join("tests", "wpt", "update_css.py"))
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run_file = path.abspath(path.join("tests", "wpt", "update_css.py"))
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kwargs["no_patch"] = not patch
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kwargs["no_patch"] = not patch
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if kwargs["no_patch"] and kwargs["sync"]:
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print("Are you sure you don't want a patch?")
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return 1
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run_globals = {"__file__": run_file}
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run_globals = {"__file__": run_file}
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execfile(run_file, run_globals)
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execfile(run_file, run_globals)
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return run_globals["update_tests"](**kwargs)
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return run_globals["update_tests"](**kwargs)
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