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Make image_name a function

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This commit is contained in:
Simon Sapin 2018-09-20 18:36:38 +02:00
parent c9d698fad7
commit 5f0c95db47
1 changed files with 12 additions and 11 deletions
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23
decisionlib.py
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@ -67,7 +67,7 @@ class DecisionTask:
raise
return self.create_task(
task_name="docker image build task for image: " + self.image_name(dockerfile),
task_name="docker image build task for image: " + image_name(dockerfile),
script="""
echo "$DOCKERFILE" | docker build -t taskcluster-built -
docker save taskcluster-built | lz4 > /%s
@ -94,16 +94,6 @@ class DecisionTask:
},
)
def image_name(self, dockerfile):
basename = os.path.basename(dockerfile)
suffix = ".dockerfile"
if basename == "Dockerfile":
return os.path.basename(os.path.dirname(os.path.abspath(dockerfile)))
elif basename.endswith(suffix):
return basename[:-len(suffix)]
else:
return basename
def create_task(self, *, task_name, script, max_run_time_minutes,
docker_image=None, dockerfile=None, # One of these is required
artifacts=None, dependencies=None, env=None, cache=None, scopes=None,
@ -195,5 +185,16 @@ class DecisionTask:
return task_id
def image_name(dockerfile):
basename = os.path.basename(dockerfile)
suffix = ".dockerfile"
if basename == "Dockerfile":
return os.path.basename(os.path.dirname(os.path.abspath(dockerfile)))
elif basename.endswith(suffix):
return basename[:-len(suffix)]
else:
return basename
def deindent(string):
return re.sub("\n +", " \n ", string)