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Android: run ./mach package implicitly after ./mach build by default

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The result of `./mach build` for Android is a `.so` file
that cannot be used on its own, so running build without package
is presumably never useful.
This commit is contained in:
Simon Sapin 2018-07-16 11:51:10 +02:00
parent a6f403c5f2
commit 6ef56dac2b
2 changed files with 9 additions and 2 deletions
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10
python/servo/build_commands.py
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@ -23,6 +23,7 @@ from mach.decorators import (
CommandProvider,
Command,
)
from mach.registrar import Registrar
from servo.command_base import CommandBase, cd, call, check_call, BIN_SUFFIX
from servo.util import host_triple
@ -160,6 +161,9 @@ class MachCommands(CommandBase):
default=None,
action='store_true',
help='Build for Android')
@CommandArgument('--no-package',
action='store_true',
help='For Android, disable packaging into a .apk after building')
@CommandArgument('--debug-mozjs',
default=None,
action='store_true',
@ -177,7 +181,7 @@ class MachCommands(CommandBase):
action='store_true',
help='Enable debug assertions in release')
def build(self, target=None, release=False, dev=False, jobs=None,
features=None, android=None, verbose=False, very_verbose=False,
features=None, android=None, no_package=False, verbose=False, very_verbose=False,
debug_mozjs=False, params=None, with_debug_assertions=False):
opts = params or []
@ -357,6 +361,10 @@ class MachCommands(CommandBase):
# Do some additional things if the build succeeded
if status == 0:
if android and not no_package:
Registrar.dispatch("package", context=self.context,
release=release, dev=dev, target=target)
if sys.platform == "win32":
servo_exe_dir = path.join(base_path, "debug" if dev else "release")