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style: Keep dirty bit invariants during invalidation.

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There's the question of whether should we be recursing into the invalidation
code for elements without data... Probably not, but that's a somewhat more
risky change.

Bug: 1391444
Signed-off-by: Emilio Cobos Álvarez <emilio@crisal.io>
This commit is contained in:
Emilio Cobos Álvarez 2017-08-21 16:37:47 +02:00
parent d4e43d9d76
commit aa0c320f4f
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1 changed files with 11 additions and 2 deletions
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13
components/style/invalidation/element/invalidator.rs
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@ -29,6 +29,15 @@ pub struct TreeStyleInvalidator<'a, 'b: 'a, E>
where E: TElement,
{
element: E,
// TODO(emilio): It's tempting enough to just avoid running invalidation for
// elements without data.
//
// But that's be wrong for sibling invalidations when a new element has been
// inserted in the tree and still has no data (though I _think_ the slow
// selector bits save us, it'd be nice not to depend on them).
//
// Seems like we could at least avoid running invalidation for the
// descendants if an element has no data, though.
data: Option<&'a mut ElementData>,
shared_context: &'a SharedStyleContext<'b>,
}
@ -353,7 +362,7 @@ impl<'a, 'b: 'a, E> TreeStyleInvalidator<'a, 'b, E>
//
// Since we keep the traversal flags in terms of the flattened tree,
// we need to propagate it as appropriate.
if invalidated_child {
if invalidated_child && child.get_data().is_some() {
let mut current = child.traversal_parent();
while let Some(parent) = current.take() {
if parent == self.element {
@ -470,7 +479,7 @@ impl<'a, 'b: 'a, E> TreeStyleInvalidator<'a, 'b, E>
any_descendant |= self.invalidate_nac(invalidations);
if any_descendant {
if any_descendant && self.data.as_ref().map_or(false, |d| !d.styles.is_display_none()) {
unsafe { self.element.set_dirty_descendants() };
}