Mirrors/servo
1
0
Fork 0
mirror of https://github.com/servo/servo.git synced 2025-07-03 05:23:38 +01:00
Code Issues Projects Releases Packages Wiki Activity

Don't assume that inputs to compute_style_with_inputs have any rules.

Browse source 
It could be a text style, which never has any rules attached to it.

Fixes https://bugzilla.mozilla.org/show_bug.cgi?id=1406222
This commit is contained in:
Boris Zbarsky 2017-10-05 23:16:14 -04:00
parent f3191db2b1
commit b488b321ed
1 changed files with 4 additions and 4 deletions
Download patch file Download diff file Expand all files Collapse all files

8
components/style/stylist.rs
View file

@ -894,12 +894,12 @@ impl Stylist {
// We need to compute visited values if we have visited rules or if our
// parent has visited values.
let visited_values = if inputs.visited_rules.is_some() || parent_style.visited_style().is_some() {
// Slightly annoying: we know that inputs has either rules or
// visited rules, but we can't do inputs.rules() up front because
// maybe it just has visited rules, so can't unwrap_or.
// At this point inputs may have visited rules, or rules, or both,
// or neither (e.g. if it's a text style it may have neither). So
// we have to be a bit careful here.
let rule_node = match inputs.visited_rules.as_ref() {
Some(rules) => rules,
None => inputs.rules.as_ref().unwrap(),
None => inputs.rules.as_ref().unwrap_or(self.rule_tree().root()),
};
let inherited_style;
let inherited_style_ignoring_first_line;