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style: Correct style sharing handling for any element that considered :has() in selector matching

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For any element that anchors a `:has()` selector (i.e. Matches a selector that
contains a `:has()` on its rightmost side), we prevent style sharing altogether,
as evaluation of the `:has()` selector is required in the first place to
determine style sharing.

On the other hand, any element matching a rule containing `:has()` without
anchoring it can do style sharing for siblings, but not cousins.

Differential Revision: https://phabricator.services.mozilla.com/D176836
This commit is contained in:
David Shin 2023-05-25 14:35:18 +00:00 • committed by Martin Robinson
parent 5c0897c8eb
commit ff8100d396
9 changed files with 91 additions and 6 deletions
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3
components/selectors/context.rs
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@ -146,6 +146,7 @@ where
/// The current element we're anchoring on for evaluating the relative selector.
current_relative_selector_anchor: Option<OpaqueElement>,
pub considered_relative_selector: bool,
quirks_mode: QuirksMode,
needs_selector_flags: NeedsSelectorFlags,
@ -199,6 +200,7 @@ where
pseudo_element_matching_fn: None,
extra_data: Default::default(),
current_relative_selector_anchor: None,
considered_relative_selector: false,
_impl: ::std::marker::PhantomData,
}
}
@ -332,6 +334,7 @@ where
self.current_relative_selector_anchor = Some(anchor);
let result = self.nest(f);
self.current_relative_selector_anchor = original_relative_selector_anchor;
self.considered_relative_selector = true;
result
}